#### Answer

$I = 1.8\times 10^{-8}~A$

#### Work Step by Step

We can find the average current:
$I = \frac{Q}{t}$
$I = \frac{9.0\times 10^{-12}~C}{0.50\times 10^{-3}~s}$
$I = 1.8\times 10^{-8}~A$

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Published by
Pearson

ISBN 10:
0133942651

ISBN 13:
978-0-13394-265-1

$I = 1.8\times 10^{-8}~A$

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